# Solving Word Problems Using Quadratic Equations

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Baring errors does mine match your expected result?

Quadratic applications are very helpful in solving several types of word problems (other than the bouquet throwing problem), especially where optimization is involved.

What is the maximum height the ball reaches, and how far (horizontally) from Audrey does is the ball at its maximum height?

How far does the ball travel before it hits the ground?

To get the vertex, we can use ($$\displaystyle -\frac$$, plug $$\displaystyle -\frac$$ into the $$t$$ to get the $$y$$) to find the coordinates of the vertex, when $$y=a bt c$$: $$\displaystyle -\frac=-\frac=\,\,\,\,3.125\, \text$$ (This is the time, and to get the height, we plug this into $$-16 100t$$, and get ; we get $$t=6.25$$ seconds. This makes sense, since the ball started from the ground, so the parabola is symmetrical around the line of symmetry, which is $$x=3.125$$.

The reasonable domain is $$\left[ \right]$$ and the reasonable range is $$\left[ \right]$$. Hit ENTER once more, and you have your zero, which is (We will discuss projectile motion using parametric equations here in the Parametric Equations section.) Note that the independent variable represents time, not distance; sometimes parabolas represent the distance on the $$x$$-axis and the height on the $$y$$-axis, and the shapes are similar.Student difficulties in solving symbolic problems were mainly associated with arithmetic and algebraic manipulation errors.In the word problems, however, students had difficulties comprehending the context and were therefore unable to formulate the equation to be solved.Data was collected through an open-ended questionnaire comprising eight symbolic equations and four word problems; furthermore, semi-structured interviews were conducted with sixteen of the students.In the data analysis, the percentage of the students’ correct, incorrect, blank, and incomplete responses was determined to obtain an overview of student performance in solving symbolic equations and word problems.The amount of effort you invest in practicing solving word problems will be directional proportional to your mastery of them.Lastly, quadratic equation word problems are interesting and I think fun- really study hard as these type of problems are on many tests to include the SAT/ACT.Thus, it is concluded that the differences in the structural properties of the symbolic equations and word problem representations affected student performance in formulating and solving quadratic equations with one unknown.In this lesson I will teach you about quadratic equation word problems.Two pedestrians simultaneously head towards each other from two different locations. The first says that by combining their speeds, the two pedestrians cover the 76 km in six hours: $$= 6\text\cdot60\text.$$ I’m measuring the speeds in km/min, so the time is converted into minutes. How much time does individual pedestrian need in order to walk 1km of path, if the first pedestrians walks this path of 1km one minute less than the other pedestrian? The second one takes $\frac v-1$ minutes to walk

The reasonable domain is $$\left[ \right]$$ and the reasonable range is $$\left[ \right]$$. Hit ENTER once more, and you have your zero, which is (We will discuss projectile motion using parametric equations here in the Parametric Equations section.) Note that the independent variable represents time, not distance; sometimes parabolas represent the distance on the $$x$$-axis and the height on the $$y$$-axis, and the shapes are similar.

Student difficulties in solving symbolic problems were mainly associated with arithmetic and algebraic manipulation errors.

In the word problems, however, students had difficulties comprehending the context and were therefore unable to formulate the equation to be solved.

Data was collected through an open-ended questionnaire comprising eight symbolic equations and four word problems; furthermore, semi-structured interviews were conducted with sixteen of the students.

In the data analysis, the percentage of the students’ correct, incorrect, blank, and incomplete responses was determined to obtain an overview of student performance in solving symbolic equations and word problems.

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The reasonable domain is $$\left[ \right]$$ and the reasonable range is $$\left[ \right]$$. Hit ENTER once more, and you have your zero, which is (We will discuss projectile motion using parametric equations here in the Parametric Equations section.) Note that the independent variable represents time, not distance; sometimes parabolas represent the distance on the $$x$$-axis and the height on the $$y$$-axis, and the shapes are similar.Student difficulties in solving symbolic problems were mainly associated with arithmetic and algebraic manipulation errors.In the word problems, however, students had difficulties comprehending the context and were therefore unable to formulate the equation to be solved.Data was collected through an open-ended questionnaire comprising eight symbolic equations and four word problems; furthermore, semi-structured interviews were conducted with sixteen of the students.In the data analysis, the percentage of the students’ correct, incorrect, blank, and incomplete responses was determined to obtain an overview of student performance in solving symbolic equations and word problems.The amount of effort you invest in practicing solving word problems will be directional proportional to your mastery of them.Lastly, quadratic equation word problems are interesting and I think fun- really study hard as these type of problems are on many tests to include the SAT/ACT.Thus, it is concluded that the differences in the structural properties of the symbolic equations and word problem representations affected student performance in formulating and solving quadratic equations with one unknown.In this lesson I will teach you about quadratic equation word problems.Two pedestrians simultaneously head towards each other from two different locations. The first says that by combining their speeds, the two pedestrians cover the 76 km in six hours: $$= 6\text\cdot60\text.$$ I’m measuring the speeds in km/min, so the time is converted into minutes. How much time does individual pedestrian need in order to walk 1km of path, if the first pedestrians walks this path of 1km one minute less than the other pedestrian? The second one takes $\frac v-1$ minutes to walk $1$ km. We then get $$76=6v 6\cdot \frac$$ Using the formula $t=d/v$, you can write down two equations from the statements in the problem.

$km. We then get$=6v 6\cdot \frac  Using the formula $t=d/v$, you can write down two equations from the statements in the problem.

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Your v−160 for the slower one is incorrect. You are measuring v in km/hour. If the first one walks v km/hour, he takes 60v minutes to walk 1 km.…